3.329 \(\int \frac {\log ^3(c (a+b x)^n)}{d+e x^2} \, dx\)

Optimal. Leaf size=477 \[ \frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (\frac {\sqrt {e} (a+b x)}{\sqrt {e} a+b \sqrt {-d}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (\frac {\sqrt {e} (a+b x)}{\sqrt {e} a+b \sqrt {-d}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{a \sqrt {e}+b \sqrt {-d}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {3 n^3 \text {Li}_4\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}+\frac {3 n^3 \text {Li}_4\left (\frac {\sqrt {e} (a+b x)}{\sqrt {e} a+b \sqrt {-d}}\right )}{\sqrt {-d} \sqrt {e}} \]

[Out]

1/2*ln(c*(b*x+a)^n)^3*ln(b*((-d)^(1/2)-x*e^(1/2))/(b*(-d)^(1/2)+a*e^(1/2)))/(-d)^(1/2)/e^(1/2)-1/2*ln(c*(b*x+a
)^n)^3*ln(b*((-d)^(1/2)+x*e^(1/2))/(b*(-d)^(1/2)-a*e^(1/2)))/(-d)^(1/2)/e^(1/2)-3/2*n*ln(c*(b*x+a)^n)^2*polylo
g(2,-(b*x+a)*e^(1/2)/(b*(-d)^(1/2)-a*e^(1/2)))/(-d)^(1/2)/e^(1/2)+3/2*n*ln(c*(b*x+a)^n)^2*polylog(2,(b*x+a)*e^
(1/2)/(b*(-d)^(1/2)+a*e^(1/2)))/(-d)^(1/2)/e^(1/2)+3*n^2*ln(c*(b*x+a)^n)*polylog(3,-(b*x+a)*e^(1/2)/(b*(-d)^(1
/2)-a*e^(1/2)))/(-d)^(1/2)/e^(1/2)-3*n^2*ln(c*(b*x+a)^n)*polylog(3,(b*x+a)*e^(1/2)/(b*(-d)^(1/2)+a*e^(1/2)))/(
-d)^(1/2)/e^(1/2)-3*n^3*polylog(4,-(b*x+a)*e^(1/2)/(b*(-d)^(1/2)-a*e^(1/2)))/(-d)^(1/2)/e^(1/2)+3*n^3*polylog(
4,(b*x+a)*e^(1/2)/(b*(-d)^(1/2)+a*e^(1/2)))/(-d)^(1/2)/e^(1/2)

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Rubi [A]  time = 0.54, antiderivative size = 477, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 6, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {2409, 2396, 2433, 2374, 2383, 6589} \[ \frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {PolyLog}\left (3,-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {PolyLog}\left (3,\frac {\sqrt {e} (a+b x)}{a \sqrt {e}+b \sqrt {-d}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {PolyLog}\left (2,-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {PolyLog}\left (2,\frac {\sqrt {e} (a+b x)}{a \sqrt {e}+b \sqrt {-d}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {3 n^3 \text {PolyLog}\left (4,-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}+\frac {3 n^3 \text {PolyLog}\left (4,\frac {\sqrt {e} (a+b x)}{a \sqrt {e}+b \sqrt {-d}}\right )}{\sqrt {-d} \sqrt {e}}+\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{a \sqrt {e}+b \sqrt {-d}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}} \]

Antiderivative was successfully verified.

[In]

Int[Log[c*(a + b*x)^n]^3/(d + e*x^2),x]

[Out]

(Log[c*(a + b*x)^n]^3*Log[(b*(Sqrt[-d] - Sqrt[e]*x))/(b*Sqrt[-d] + a*Sqrt[e])])/(2*Sqrt[-d]*Sqrt[e]) - (Log[c*
(a + b*x)^n]^3*Log[(b*(Sqrt[-d] + Sqrt[e]*x))/(b*Sqrt[-d] - a*Sqrt[e])])/(2*Sqrt[-d]*Sqrt[e]) - (3*n*Log[c*(a
+ b*x)^n]^2*PolyLog[2, -((Sqrt[e]*(a + b*x))/(b*Sqrt[-d] - a*Sqrt[e]))])/(2*Sqrt[-d]*Sqrt[e]) + (3*n*Log[c*(a
+ b*x)^n]^2*PolyLog[2, (Sqrt[e]*(a + b*x))/(b*Sqrt[-d] + a*Sqrt[e])])/(2*Sqrt[-d]*Sqrt[e]) + (3*n^2*Log[c*(a +
b*x)^n]*PolyLog[3, -((Sqrt[e]*(a + b*x))/(b*Sqrt[-d] - a*Sqrt[e]))])/(Sqrt[-d]*Sqrt[e]) - (3*n^2*Log[c*(a + b
*x)^n]*PolyLog[3, (Sqrt[e]*(a + b*x))/(b*Sqrt[-d] + a*Sqrt[e])])/(Sqrt[-d]*Sqrt[e]) - (3*n^3*PolyLog[4, -((Sqr
t[e]*(a + b*x))/(b*Sqrt[-d] - a*Sqrt[e]))])/(Sqrt[-d]*Sqrt[e]) + (3*n^3*PolyLog[4, (Sqrt[e]*(a + b*x))/(b*Sqrt
[-d] + a*Sqrt[e])])/(Sqrt[-d]*Sqrt[e])

Rule 2374

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> -Sim
p[(PolyLog[2, -(d*f*x^m)]*(a + b*Log[c*x^n])^p)/m, x] + Dist[(b*n*p)/m, Int[(PolyLog[2, -(d*f*x^m)]*(a + b*Log
[c*x^n])^(p - 1))/x, x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 2383

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*PolyLog[k_, (e_.)*(x_)^(q_.)])/(x_), x_Symbol] :> Simp[(PolyL
og[k + 1, e*x^q]*(a + b*Log[c*x^n])^p)/q, x] - Dist[(b*n*p)/q, Int[(PolyLog[k + 1, e*x^q]*(a + b*Log[c*x^n])^(
p - 1))/x, x], x] /; FreeQ[{a, b, c, e, k, n, q}, x] && GtQ[p, 0]

Rule 2396

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*
(f + g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n])^p)/g, x] - Dist[(b*e*n*p)/g, Int[(Log[(e*(f + g*x))/(e*f -
d*g)]*(a + b*Log[c*(d + e*x)^n])^(p - 1))/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && NeQ[e*
f - d*g, 0] && IGtQ[p, 1]

Rule 2409

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_)^(r_))^(q_.), x_Symbol] :> In
t[ExpandIntegrand[(a + b*Log[c*(d + e*x)^n])^p, (f + g*x^r)^q, x], x] /; FreeQ[{a, b, c, d, e, f, g, n, r}, x]
&& IGtQ[p, 0] && IntegerQ[q] && (GtQ[q, 0] || (IntegerQ[r] && NeQ[r, 1]))

Rule 2433

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + Log[(h_.)*((i_.) + (j_.)*(x_))^(m_.)]*
(g_.))*((k_.) + (l_.)*(x_))^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[((k*x)/d)^r*(a + b*Log[c*x^n])^p*(f + g*Lo
g[h*((e*i - d*j)/e + (j*x)/e)^m]), x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, j, k, l, n, p, r},
x] && EqQ[e*k - d*l, 0]

Rule 6589

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps

\begin {align*} \int \frac {\log ^3\left (c (a+b x)^n\right )}{d+e x^2} \, dx &=\int \left (\frac {\sqrt {-d} \log ^3\left (c (a+b x)^n\right )}{2 d \left (\sqrt {-d}-\sqrt {e} x\right )}+\frac {\sqrt {-d} \log ^3\left (c (a+b x)^n\right )}{2 d \left (\sqrt {-d}+\sqrt {e} x\right )}\right ) \, dx\\ &=-\frac {\int \frac {\log ^3\left (c (a+b x)^n\right )}{\sqrt {-d}-\sqrt {e} x} \, dx}{2 \sqrt {-d}}-\frac {\int \frac {\log ^3\left (c (a+b x)^n\right )}{\sqrt {-d}+\sqrt {e} x} \, dx}{2 \sqrt {-d}}\\ &=\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {(3 b n) \int \frac {\log ^2\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{b \sqrt {-d}+a \sqrt {e}}\right )}{a+b x} \, dx}{2 \sqrt {-d} \sqrt {e}}+\frac {(3 b n) \int \frac {\log ^2\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{a+b x} \, dx}{2 \sqrt {-d} \sqrt {e}}\\ &=\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {(3 n) \operatorname {Subst}\left (\int \frac {\log ^2\left (c x^n\right ) \log \left (\frac {b \left (\frac {b \sqrt {-d}+a \sqrt {e}}{b}-\frac {\sqrt {e} x}{b}\right )}{b \sqrt {-d}+a \sqrt {e}}\right )}{x} \, dx,x,a+b x\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {(3 n) \operatorname {Subst}\left (\int \frac {\log ^2\left (c x^n\right ) \log \left (\frac {b \left (\frac {b \sqrt {-d}-a \sqrt {e}}{b}+\frac {\sqrt {e} x}{b}\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{x} \, dx,x,a+b x\right )}{2 \sqrt {-d} \sqrt {e}}\\ &=\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {\left (3 n^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (c x^n\right ) \text {Li}_2\left (-\frac {\sqrt {e} x}{b \sqrt {-d}-a \sqrt {e}}\right )}{x} \, dx,x,a+b x\right )}{\sqrt {-d} \sqrt {e}}-\frac {\left (3 n^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (c x^n\right ) \text {Li}_2\left (\frac {\sqrt {e} x}{b \sqrt {-d}+a \sqrt {e}}\right )}{x} \, dx,x,a+b x\right )}{\sqrt {-d} \sqrt {e}}\\ &=\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}+a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {\left (3 n^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_3\left (-\frac {\sqrt {e} x}{b \sqrt {-d}-a \sqrt {e}}\right )}{x} \, dx,x,a+b x\right )}{\sqrt {-d} \sqrt {e}}+\frac {\left (3 n^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_3\left (\frac {\sqrt {e} x}{b \sqrt {-d}+a \sqrt {e}}\right )}{x} \, dx,x,a+b x\right )}{\sqrt {-d} \sqrt {e}}\\ &=\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}-\sqrt {e} x\right )}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {\log ^3\left (c (a+b x)^n\right ) \log \left (\frac {b \left (\sqrt {-d}+\sqrt {e} x\right )}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}-\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {3 n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}+a \sqrt {e}}\right )}{2 \sqrt {-d} \sqrt {e}}+\frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {3 n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}+a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}-\frac {3 n^3 \text {Li}_4\left (-\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}-a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}+\frac {3 n^3 \text {Li}_4\left (\frac {\sqrt {e} (a+b x)}{b \sqrt {-d}+a \sqrt {e}}\right )}{\sqrt {-d} \sqrt {e}}\\ \end {align*}

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Mathematica [C]  time = 0.33, size = 754, normalized size = 1.58 \[ \frac {-6 i n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (\frac {\sqrt {e} (a+b x)}{a \sqrt {e}-i b \sqrt {d}}\right )+6 i n^2 \log \left (c (a+b x)^n\right ) \text {Li}_3\left (\frac {\sqrt {e} (a+b x)}{\sqrt {e} a+i b \sqrt {d}}\right )-3 i n^2 \log ^2(a+b x) \log \left (c (a+b x)^n\right ) \log \left (1-\frac {\sqrt {e} (a+b x)}{a \sqrt {e}-i b \sqrt {d}}\right )+3 i n^2 \log ^2(a+b x) \log \left (c (a+b x)^n\right ) \log \left (1-\frac {\sqrt {e} (a+b x)}{a \sqrt {e}+i b \sqrt {d}}\right )+6 n^2 \log ^2(a+b x) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \log \left (c (a+b x)^n\right )+3 i n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (\frac {\sqrt {e} (a+b x)}{a \sqrt {e}-i b \sqrt {d}}\right )-3 i n \log ^2\left (c (a+b x)^n\right ) \text {Li}_2\left (\frac {\sqrt {e} (a+b x)}{\sqrt {e} a+i b \sqrt {d}}\right )+3 i n \log (a+b x) \log ^2\left (c (a+b x)^n\right ) \log \left (1-\frac {\sqrt {e} (a+b x)}{a \sqrt {e}-i b \sqrt {d}}\right )-3 i n \log (a+b x) \log ^2\left (c (a+b x)^n\right ) \log \left (1-\frac {\sqrt {e} (a+b x)}{a \sqrt {e}+i b \sqrt {d}}\right )+2 \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \log ^3\left (c (a+b x)^n\right )-6 n \log (a+b x) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \log ^2\left (c (a+b x)^n\right )+6 i n^3 \text {Li}_4\left (\frac {\sqrt {e} (a+b x)}{a \sqrt {e}-i b \sqrt {d}}\right )-6 i n^3 \text {Li}_4\left (\frac {\sqrt {e} (a+b x)}{\sqrt {e} a+i b \sqrt {d}}\right )+i n^3 \log ^3(a+b x) \log \left (1-\frac {\sqrt {e} (a+b x)}{a \sqrt {e}-i b \sqrt {d}}\right )-i n^3 \log ^3(a+b x) \log \left (1-\frac {\sqrt {e} (a+b x)}{a \sqrt {e}+i b \sqrt {d}}\right )-2 n^3 \log ^3(a+b x) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{2 \sqrt {d} \sqrt {e}} \]

Antiderivative was successfully verified.

[In]

Integrate[Log[c*(a + b*x)^n]^3/(d + e*x^2),x]

[Out]

(-2*n^3*ArcTan[(Sqrt[e]*x)/Sqrt[d]]*Log[a + b*x]^3 + 6*n^2*ArcTan[(Sqrt[e]*x)/Sqrt[d]]*Log[a + b*x]^2*Log[c*(a
+ b*x)^n] - 6*n*ArcTan[(Sqrt[e]*x)/Sqrt[d]]*Log[a + b*x]*Log[c*(a + b*x)^n]^2 + 2*ArcTan[(Sqrt[e]*x)/Sqrt[d]]
*Log[c*(a + b*x)^n]^3 + I*n^3*Log[a + b*x]^3*Log[1 - (Sqrt[e]*(a + b*x))/((-I)*b*Sqrt[d] + a*Sqrt[e])] - (3*I)
*n^2*Log[a + b*x]^2*Log[c*(a + b*x)^n]*Log[1 - (Sqrt[e]*(a + b*x))/((-I)*b*Sqrt[d] + a*Sqrt[e])] + (3*I)*n*Log
[a + b*x]*Log[c*(a + b*x)^n]^2*Log[1 - (Sqrt[e]*(a + b*x))/((-I)*b*Sqrt[d] + a*Sqrt[e])] - I*n^3*Log[a + b*x]^
3*Log[1 - (Sqrt[e]*(a + b*x))/(I*b*Sqrt[d] + a*Sqrt[e])] + (3*I)*n^2*Log[a + b*x]^2*Log[c*(a + b*x)^n]*Log[1 -
(Sqrt[e]*(a + b*x))/(I*b*Sqrt[d] + a*Sqrt[e])] - (3*I)*n*Log[a + b*x]*Log[c*(a + b*x)^n]^2*Log[1 - (Sqrt[e]*(
a + b*x))/(I*b*Sqrt[d] + a*Sqrt[e])] + (3*I)*n*Log[c*(a + b*x)^n]^2*PolyLog[2, (Sqrt[e]*(a + b*x))/((-I)*b*Sqr
t[d] + a*Sqrt[e])] - (3*I)*n*Log[c*(a + b*x)^n]^2*PolyLog[2, (Sqrt[e]*(a + b*x))/(I*b*Sqrt[d] + a*Sqrt[e])] -
(6*I)*n^2*Log[c*(a + b*x)^n]*PolyLog[3, (Sqrt[e]*(a + b*x))/((-I)*b*Sqrt[d] + a*Sqrt[e])] + (6*I)*n^2*Log[c*(a
+ b*x)^n]*PolyLog[3, (Sqrt[e]*(a + b*x))/(I*b*Sqrt[d] + a*Sqrt[e])] + (6*I)*n^3*PolyLog[4, (Sqrt[e]*(a + b*x)
)/((-I)*b*Sqrt[d] + a*Sqrt[e])] - (6*I)*n^3*PolyLog[4, (Sqrt[e]*(a + b*x))/(I*b*Sqrt[d] + a*Sqrt[e])])/(2*Sqrt
[d]*Sqrt[e])

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fricas [F]  time = 0.43, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\log \left ({\left (b x + a\right )}^{n} c\right )^{3}}{e x^{2} + d}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(c*(b*x+a)^n)^3/(e*x^2+d),x, algorithm="fricas")

[Out]

integral(log((b*x + a)^n*c)^3/(e*x^2 + d), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\log \left ({\left (b x + a\right )}^{n} c\right )^{3}}{e x^{2} + d}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(c*(b*x+a)^n)^3/(e*x^2+d),x, algorithm="giac")

[Out]

integrate(log((b*x + a)^n*c)^3/(e*x^2 + d), x)

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maple [F]  time = 13.43, size = 0, normalized size = 0.00 \[ \int \frac {\ln \left (c \left (b x +a \right )^{n}\right )^{3}}{e \,x^{2}+d}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln(c*(b*x+a)^n)^3/(e*x^2+d),x)

[Out]

int(ln(c*(b*x+a)^n)^3/(e*x^2+d),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\log \left ({\left (b x + a\right )}^{n} c\right )^{3}}{e x^{2} + d}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(c*(b*x+a)^n)^3/(e*x^2+d),x, algorithm="maxima")

[Out]

integrate(log((b*x + a)^n*c)^3/(e*x^2 + d), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\ln \left (c\,{\left (a+b\,x\right )}^n\right )}^3}{e\,x^2+d} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(log(c*(a + b*x)^n)^3/(d + e*x^2),x)

[Out]

int(log(c*(a + b*x)^n)^3/(d + e*x^2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\log {\left (c \left (a + b x\right )^{n} \right )}^{3}}{d + e x^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(c*(b*x+a)**n)**3/(e*x**2+d),x)

[Out]

Integral(log(c*(a + b*x)**n)**3/(d + e*x**2), x)

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